q )
(r
q) does not have the truth table as claimed in column 4,
we can check that its first two rows match the semantics of that
formula. However, in row 3 the atoms p and r are true and q is false.
This makes the implication
(p
q) false. Moreover,
it makes the conjunction
(r
q) true, and so
(r
q) is false. Thus, the entire formula evaluates to
F, as its two disjuncts do so. This contradicts the entry
in row 3 of column 4.