Incorrect Answer.

For the relation par T if (x > 5) { y = x - 1;} else {y = x + 1;} y > 3 to hold, it has to be the case that at any state satisfying T ("true"), if the program in question terminates, then the resulting store satisfies "y > 3". This is not the case. For example, if we consider the initial store in which the value stored in x equals 2, then the boolean guard "(x > 5)" of the if-statement evaluates to "false", so the else-branch, "y = x + 1;" of the if-statement gets executed, assigning to y the current value stored in x plus one, that is 2 + 1, which is 3. Thus, the program terminates in a state in which the value of y is not greater than 3. This violates the claimed relationship above.
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